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(B) The speed of sound $v$ in a gas is given by the relation $v \propto \sqrt{T}$,where $T$ is the absolute temperature in Kelvin.Let $v_0$ be the spe

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$1092$

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(B) The speed of sound $v$ in a gas is given by the relation $v \propto \sqrt{T}$,where $T$ is the absolute temperature in Kelvin.Let $v_0$ be the speed of sound at $0\,^oC$ $(T_0 = 273\,K)$.Let $v_t$ be the speed of sound at temperature $T$.According to the problem,$v_t = 2v_0$.Using the relation $\frac{v_t}{v_0} = \sqrt{\frac{T}{T_0}}$,we get:$2 = \sqrt{\frac{T}{273}}$Squaring both sides,we get $4 = \frac{T}{273}$.Therefore,$T = 4 	imes 273 = 1092\,K$.

Calculate the temperature at which the speed of sound will be two times its value at $0\,^oC$. (in $,K$)

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